How do you solve $9 - \sqrt[3]{3 x - 5} = 7$ $9- root[ 3] { 3x - 5} = 7$ ?

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How do you solve $9 - \sqrt[3]{3 x - 5} = 7$ $9- root[ 3] { 3x - 5} = 7$ ?

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Answer 1 · 2017-07-08T12:03:14

$x = \frac{13}{3} or 4.333333333$ $x=13/3 or 4.333333333$

Explanation:

$9 - \sqrt[3]{3 x - 5} = 7$ $9-root3(3x-5)=7$

$:.-root3(3x-5)=7-9$

$:.-root3(3x-5)=-2$

multiply both sides by $-1$

$:.root3(3x-5)=2$

cube both sides

$:.(root3(3x-5))^3=(2)^3$

$:.root3a*root3a*root3a=a$

$:.3x-5=2^3$

$:.3x-5=8$

$:.3x=8+5$

$:.3x=13$

$:.color(blue)(x=13/3 or 4.333333333$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$color(blue)(Check:$

substitute $color(blue)(x=4.333333333$

$:.9-root3(3(color(blue)4.333333333)-5)=7$

$:.9-root3(13-5)=7$

$:.-root3(13-5)=7-9$

$:.-root3(8)=-2$

Multiply both sides by $-1$

$:.root3(2*2*2)=2$

$:.root3(2)*root3(2)*root3(2)=2$

$:.color(blue)(2=2$

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How do you solve $9 - \sqrt[3]{3 x - 5} = 7$ $9- root[ 3] { 3x - 5} = 7$ ?

1 Answer

Explanation:

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How do you solve $9 - \sqrt[3]{3 x - 5} = 7$ $9- root[ 3] { 3x - 5} = 7$ ?