How do you solve $9 {(2 m - 3)}^{2} + 8 = 449$ $9(2m-3)^2+8=449$ ?

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Answer 1 · 2016-10-04T02:08:35

$m = - 2 or 5$ $m= -2 or 5$

$9 {(2 m - 3)}^{2} + 8 = 449$ $9(2m-3)^2+8=449$

$9 {(2 m - 3)}^{2} = 441$ $9(2m-3)^2 = 441$

${(2 m - 3)}^{2} = \frac{441}{9} = 49$ $(2m-3)^2 = 441/9 = 49$

$2 m - 3 = \sqrt{49} = \pm 7$ $2m-3 = sqrt(49) = +-7$

$2 m = \pm 7 + 3$ $2m = +-7 +3$

$2 m = - 4 or 10$ $2m = -4 or 10$

$m = - 2 or 5$ $m=-2 or 5$

How do you solve 9(2m−3)2+8=4499(2m-3)^2+8=449?