How do you solve #9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2#?
1 Answer
Aug 28, 2017
Explanation:
#"when evaluating expressions with "color(blue)"mixed operations"#
#"there is a particular order that must be followed"#
#"follow the order as set out in the acronym PEMDAS"# [P-parenthesis (brackets), E-exponents (powers), M-multiplication, D-division, A- addition, S-subtraction ]
#"multiplication/division have equal precedence so when"#
#"they occur in the same expression evaluate from left"#
#"to right. This is also the case with addition/subtraction"#
#9-16xx(2^2-1^3)/(2(-4))-8-:2#
#=9-cancel(16)^-2xx(4-1)/(cancel(-8)^1)-8-:2larrcolor(red)"P/E"#
#=9-(-2xx3)-8-:2larrcolor(red)" tidy up fraction"#
#=9-(-6)-4larrcolor(red)" multiplication/division"#
#=9+6-4larrcolor(red)" evaluate left to right"#
#=11#
