How do you solve $9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2$ ?

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How do you solve $9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2$ ?

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Answer 1 · 2017-08-28T09:26:16

$11$

Explanation:

$"when evaluating expressions with "color(blue)"mixed operations"$
$"there is a particular order that must be followed"$

$"follow the order as set out in the acronym PEMDAS"$

[P-parenthesis (brackets), E-exponents (powers), M-multiplication, D-division, A- addition, S-subtraction ]

$"multiplication/division have equal precedence so when"$
$"they occur in the same expression evaluate from left"$
$"to right. This is also the case with addition/subtraction"$

$9-16xx(2^2-1^3)/(2(-4))-8-:2$

$=9-cancel(16)^-2xx(4-1)/(cancel(-8)^1)-8-:2larrcolor(red)"P/E"$

$=9-(-2xx3)-8-:2larrcolor(red)" tidy up fraction"$

$=9-(-6)-4larrcolor(red)" multiplication/division"$

$=9+6-4larrcolor(red)" evaluate left to right"$

$=11$

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How do you solve $9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2$ ?

1 Answer

Explanation:

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How do you solve 9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 29- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2?

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How do you solve $9- 16\cdot \frac{2^{2} - 1^{3}}{2( - 4)} - 8\div 2$ ?