How do you solve #8x^2+ 7 = 9x^2+ 10#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer flaxar · Stefan V. Nov 9, 2015 #8x^2 + 7 = 9x^2 + 10# #8x^2 -9x^2 = 10 - 7# #-x^2 = 3# #x^2 = -3# #x = sqrt3# Explanation: first, you separate and move the number to the other side and #x^2# to the other side. then solve it. #x^2# when we bring to the other side will become square root. :) Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1409 views around the world You can reuse this answer Creative Commons License