How do you solve # 8x^2 = 24x#?

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Answer 1 · 2018-06-11T07:38:11

#x = 0# or #x = 3#

Bring everything to left hand side:

#8x^2 - 24x = 0#

Factor #8x#:

#8x(x-3)=0#

A multiplication equals zero if and only if at least one of the factors equals zero: so it must be either

#8x = 0 \iff x = 0#

or

#x-3 = 0 \iff x=3#