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How do you solve $8 n^{2} - 4 = 532$ $8n^2-4=532$ ?

1 Answer

Jul 31, 2016

$n = \pm \sqrt{67}$ $n=+-sqrt67$

Explanation:

$8 n^{2} - 4 = 532 or 8 n^{2} = 536 or n^{2} = 67 or n = \pm \sqrt{67}$ $8n^2-4=532 or 8n^2=536 or n^2=67 or n=+-sqrt67$ [Ans]

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