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How do you solve $8 cos x - 4 \sqrt{2} = 0$ $8cosx-4sqrt2=0$ ?

1 Answer

May 13, 2018

$x = 45^{\circ}$ $x=45^@$

Explanation:

$8 cos x - 4 \sqrt{2} = 0$ $8cosx-4sqrt2=0$

Add $4 \sqrt{2}$ $4sqrt2$ to both sides
$8 cos x = 4 \sqrt{2}$ $8cosx=4sqrt2$

Divide both sides by 8
$cos x = \frac{\sqrt{2}}{2}$ $cosx=sqrt2/2$
$x = 45^{\circ}$ $x=45^@$

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