How do you solve #-8a+20=14#?

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Answer 1 · 2017-02-07T14:35:19

See the entire solution process below:

Step 1) Subtract #color(red)(20)# from each side of the equation to isolate the #a# term while keeping the equation balanced:

#-8a + 20 - color(red)(20) = 14 - color(red)(20)#

#-8a + 0 = -6#

#-8a = -6#

Step 2) Divide each side of the equation by #color(red)(-8)# to solve for #a# while keeping the equation balanced:

#(-8a)/color(red)(-8) = (-6)/color(red)(-8)#

#(color(red)(cancel(color(black)(-8)))a)/cancel(color(red)(-8)) = (-2 xx 3)/color(red)(-2 xx 4)#

#a = (color(red)(cancel(color(black)(-2))) xx 3)/color(red)(cancel(-2) xx 4)#

#a = 3/4#