How do you solve $- 8 + 9 x^{2} + 5 = - 9 x^{2} + 5$ $-8+9x^2+5=-9x^2+5$ ?

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How do you solve $- 8 + 9 x^{2} + 5 = - 9 x^{2} + 5$ $-8+9x^2+5=-9x^2+5$ ?

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Answer 1 · 2016-10-24T07:53:03

$x = - \frac{2}{3}, \frac{2}{3}$ $x=-2/3, 2/3$

Explanation:

Solve: $- 8 + 9 x^{2} + 5 = - 9 x^{2} + 5$ $-8+9x^2+5=-9x^2+5$

Simplify.

$9 x^{2} - 3 = - 9 x^{2} + 5$ $9x^2-3=-9x^2+5$

Add $3$ $3$ to both sides.

$9 x^{2} = - 9 x^{2} + 5 + 3$ $9x^2=-9x^2+5+3$

Add $9 x^{2}$ $9x^2$ to both sides.

$9 x^{2} + 9 x^{2} = 5 + 3$ $9x^2+9x^2=5+3$

Simplify.

$18 x^{2} = 8$ $18x^2=8$

Subtract $8$ $8$ from both sides.

$18 x^{2} - 8 = 0$ $18x^2-8=0$

This is a quadratic equation of the form $a x^{2} + b x + c$ $ax^2+bx+c$ , where $a = 18$ $a=18$ , $b = 0$ $b=0$ , $c = - 8$ $c=-8$ .

The value for $x$ $x$ can be determined using the quadratic formula.

Quadratic Formula

$x = \frac{- b \pm \sqrt{b^{2} - 4 \cdot a \cdot c}}{2 a}$ $x=(-b+-sqrt(b^2-4*a*c))/(2a)$

$x = \frac{- 0 \pm \sqrt{0^{2} - 4 \cdot 18 \cdot - 8}}{2 \cdot 18}$ $x=(-0+-sqrt(0^2-4*18*-8))/(2*18)$

Simplify.

$x = \frac{\pm \sqrt{576}}{36}$ $x=(+-sqrt(576))/36$

Simplify.

$x = \pm \frac{24}{36}$ $x=+-(24)/36$

Simplify.

$x = \pm \frac{4}{9}$ $x=+-4/9$

Simplify.

$x = \pm \frac{2}{3}$ $x=+-2/3$

$x = - \frac{2}{3}, \frac{2}{3}$ $x=-2/3, 2/3$

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How do you solve $- 8 + 9 x^{2} + 5 = - 9 x^{2} + 5$ $-8+9x^2+5=-9x^2+5$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve −8+9x2+5=−9x2+5-8+9x^2+5=-9x^2+5?

1 Answer

Explanation:

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Impact of this question

How do you solve $- 8 + 9 x^{2} + 5 = - 9 x^{2} + 5$ $-8+9x^2+5=-9x^2+5$ ?