How do you solve $-8-8p^2=-31$ ?

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Answer 1 · 2017-04-24T08:13:11

$p=+-sqrt(23/8) ~= +- 1.69558$

$-8-8p^2 = -31$

Multiply through by $-1$

$8+8p^2 = 31$

$8p^2 = 31-8 =23$

$p^2 = 23/8$

$p = +- sqrt(23/8) ~=+- 1.69558$

Answer 2 · 2017-04-24T08:15:57

Rearrange your exquation to give $p=+-sqrt(23/8)$

$-8-8p^2=-31$
$-8p^2=-23$
$p^2=23/8$
$p=+-sqrt(23/8)$

How do you solve -8-8p^2=-31-8-8p^2=-31?