How do you solve # 8+5(s-1)=18#?

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Answer 1 · 2016-06-22T16:06:02

#s=3#

To solve #8+5(s-1)=18#

Begin by distributing the #5# to the values inside the #()#

#8+5s-5=18#

Combine like terms on the left side of the equation #8-5#

#5s+3=18#

Isolate the term with the variable by additive inverse

#5scancel(+3)cancel(-3)=18-3#

#5s=15#

Isolate the variable by multiplicative inverse

#(cancel5s)/cancel5=15/5#

#s=3#