How do you solve $7x^2-5=2x+9x^2$ using the quadratic formula?

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How do you solve $7x^2-5=2x+9x^2$ using the quadratic formula?

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Answer 1 · 2017-08-10T00:47:29

$x=-(1+3i)/2,$ $x=-(1-3i)/2$

Refer to the explanation for the process.

Explanation:

Quadratic Equation

First combine like terms and rewrite the equation in standard form.

$7x^2-5=2x+9x^2$

Move all terms to the left side.

$7x^2-5-2x-9x^2=0$

Simplify.

$-2x^2-5-2x-9x^2=0$

Rewrite in standard form: $ax^2+bx+c=0$ .

$-2x^2-2x-5=0$ ,

where $a=-2$ , $b=-2$ , and $c=-5$ .

Quadratic Formula

$x=(-b+-sqrt(b^2-4ac))/(2a)$

Plug in the known values.

$x=(-(-2)+-sqrt((-2)^2-4*-2*-5))/(2*-2)$

Simplify.

$x=(2+-sqrt(-36))/(-4)$

Simplify.

$x=-(2+-6i)/(4)$

$x=-(2+6i)/(4),$ $(-2-36i)/(4)$

Reduce.

$x=-(color(red)cancel(color(black)(2^1))+color(red)cancel(color(black)(6^(3)))i)/color(red)cancel(color(black)(4^2)),$ $-(color(red)cancel(color(black)(2^1))-color(red)cancel(color(black)(6^(3)))i)/color(red)cancel(color(black)(4^2)),$

$x=-(1+3i)/2,$ $x=-(1-3i)/2$

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How do you solve $7x^2-5=2x+9x^2$ using the quadratic formula?

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Explanation:

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