How do you solve 7v^2+1=297v2+1=29?

3 Answers

v=\pm2v=±2

Explanation:

Given that

7v^2+1=297v2+1=29

7v^2=29-17v2=291

7v^2=287v2=28

v^2=28/7v2=287

v^2=4v2=4

\sqrt{v^2}=\sqrt4\quad(\text{taking square root on both sides})

|v|=2

v=\pm2

Jul 17, 2018

v=+-2

Explanation:

"subtract 1 from both sides"

7v^2=29-1=28

"divide both sides by 7"

v^2=28/7=4

color(blue)"take the square root of both sides"

v=+-sqrt4larrcolor(blue)"note plus or minus"

rArrv=+-2

Jul 17, 2018

v=+-2

Explanation:

Remember, our end goal is to isolate v. We can start by subtracting 1 from both sides. We now have

7v^2=28

Dividing both sides by 7 gives us

v^2=4

Taking the +- square root of both sides, we get

v=+-2

Hope this helps!