How do you solve #7 + sqrt[2x - 1] = 10#?

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Answer 1 · 2015-08-05T18:07:30

#x = 5#

First, start by isolating the readical on one side of the equation. This can be done by adding #-7# to both sides

#color(red)(cancel(color(black)(7))) - color(red)(cancel(color(black)(7))) + sqrt(2x-1) = 10 - 7#

#sqrt(2x-1) = 3#

To get rid of the radical term, square both sides of the equation

#(sqrt(2x-1))^2 = 3^2#

#2x-1 = 9#

#2x = 10 => x = 10/2 = color(green)(5)#