How do you solve # 7+2(3x-5) = 8-3(2x+1)#?

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Answer 1 · 2015-09-26T16:58:46

#color(blue)(x=5/4#

#7+2(3x−5)=8−3(2x+1)#

#7+2 * (3x) +2 * (- 5) =8 + (- 3) * (2x)+ (-3)* (1)#

#7+6x -10=8 - 6x -3#

#6x +6x = 8-3+10#

#12x = 15#

#x=15/12#

#color(blue)(x=5/4#