How do you solve $7/12=(a-6)/5$ ?

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Answer 1 · 2016-09-04T15:31:33

$a = 107/12$

There is one term on each side, you can get rid of the denominators by cross-multiplying.

$7/12 = (a-6)/5$

$12a-72 = 35$

$12a = 35+72$

$12a = 107$

$a = 107/12$

How do you solve 7/12=(a-6)/57/12=(a-6)/5?