How do you solve #7/12=(a-6)/5#?

Question

↳Redirected from "How are molecular compounds named?"

1917 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-04T15:31:33

#a = 107/12#

There is one term on each side, you can get rid of the denominators by cross-multiplying.

#7/12 = (a-6)/5#

#12a-72 = 35#

#12a = 35+72#

#12a = 107#

#a = 107/12#