How do you solve -6z^2 + 7z + 3 = 0 using the quadratic formula?

1 Answer
Waleed A.
Oct 13, 2015

z = -0.3333 and z = 1.5

Explanation:

Standard Quadratic Equation:

x^2 + bx + c = 0

Quadratic formula:

(-b+-sqrt(b^2 - 4ac)) / (2a)

b = constant with variable to the power 1
a = constant with variable to the power squared
c = constant.

-6z^2 + 7z + 3 = 0
In this case:

a = -6
b = 7
c= 3

put all these values

(-7 +- sqrt((7)^2 - 4(-6)(3))) / (2(-6))
(-7 +- sqrt(49 + 72)) / -12
(-7 +- sqrt(121)) / -12
(-7 +- 11) / -12
(-7 + 11) / -12 , (-7 - 11) / -12
4 / -12, -18 / -12
z = -0.3333 and z = 1.5

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