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How do you solve #-6x + 3= 2x - 1#?

1 Answer

sankarankalyanam

Mar 20, 2018

#color(blue)(x = 1/2#

Explanation:

#-6x + 3 = 2x - 1#

#3 + 1 = 2x + 6x, " x terms to R H S & constant to L H S"#

#8x = 4#

#x = cancel(4)^color(red)(1) / cancel(8)^color(red)(2) = color(blue)(1/2#

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