How do you solve $6x^2 - x - 5 = 0$ using the quadratic formula?

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Answer 1 · 2015-08-10T07:15:40

The solutions for the equation are

$color(blue)(x=1, x=-5/6$

$6x^2−x−5=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=6, b=-1, c=-5$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (-1)^2-(4*6*(-5))$

$=1 +120$

$=121$

The solutions are found using the formula

$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-1)+-sqrt(121))/(2*6) = (1+-11)/12$

$x = -10/12, color(blue)(x=-5/6$

$x=12/12, color(blue)(x=1$

How do you solve 6x^2 - x - 5 = 0 6x^2 - x - 5 = 0 using the quadratic formula?