How do you solve $6x^2+3x-15=0$ using the quadratic formula?

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Answer 1 · 2015-08-10T07:38:59

The solutions for the equation are :
$color(blue)( x=(-3+sqrt(369))/12$

$color(blue)( x=(-3-sqrt(369))/12$

$6x^2+3x−15=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=6, b=3, c=-15$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (3)^2-(4*6*-(15))$

$= 9 + 360 = 369$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-3)+-sqrt(369))/(2*6) = (-3+-sqrt(369))/12$

The solutions for the equation are :
$color(blue)( x=(-3+sqrt(369))/12$

$color(blue)( x=(-3-sqrt(369))/12$

How do you solve 6x^2+3x-15=06x^2+3x-15=0 using the quadratic formula?