How do you solve (6x+2)^2+4=28?

1 Answer
Jim G.
Jul 23, 2017

x=-1/3+-1/3sqrt6

Explanation:

"isolate " (6x+2)^2

"subtract 4 from both sides"

rArr(6x+2)^2=24

color(blue)"take the square root of both sides"

sqrt((6x+2)^2)=+-sqrt24larr" note plus or minus"

rArr6x+2=+-2sqrt6larr" simplifying radical"

"subtract 2 from both sides"

rArr6x=+-2sqrt6-2

"divide both sides by 6"

rArrx=(-2+-2sqrt6)/6

color(white)(rArrx)=-1/3+-1/3sqrt6larrcolor(red)" exact values"

x~~ 0.483" to 3 dec. places"

"or " x~~-1.15" to 2 dec. places"

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