How do you solve $6x^2 + 11x + 4$ using the quadratic formula?

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Answer 1 · 2016-03-08T15:01:10

The solutions are:
$x=-1/2$

$x=-4/3$

$6x^2 +11x +4=0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=6, b=11, c=4$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (11)^2-(4*6 * 4)$

$= 121-96=25$

The solutions are found using the formula:

$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-11)+-sqrt(25))/(2*6) = (-11+-5)/12$

$x=(-11+5)/12 =-6/12=-1/2$

$x=(-11-5)/12 =-16/12=-4/3$

How do you solve 6x^2 + 11x + 46x^2 + 11x + 4 using the quadratic formula?