How do you solve $6x²=1-x$ ?

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Answer 1 · 2016-10-04T20:34:17

$" at "y=0 :" "x=-1/2" and "x=1/3$

Write as $" "y=6x^2+x-1$

Compare to the form $" "y=ax^2+bx+c$

$color(blue)("Using the formula: "x=(-b+-sqrt(b^2-4ac))/(2a))$

$=>x=(-1+-sqrt((-1)^2-4(6)(-1)))/(2(6))$

$x=(-1+-sqrt(25))/12" "->" "x=-1/12+-5/12$

$=>" at "y=0 :" "x=-1/2" and "x=1/3$

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Tony B

How do you solve 6x²=1-x6x²=1-x?