How do you solve 6tan^2x-2=06tan2x2=0?

1 Answer
Jan 23, 2017

+- pi/3 + kpi±π3+kπ

Explanation:

6tan^2 x - 2 = 06tan2x2=0
tan^2 x = 2/6 = 1/3tan2x=26=13
tan x = +- 1/sqrt3 = +- sqrt3/3tanx=±13=±33
Trig table of special arcs and unit circle give:
a. tan x = sqrt3/3tanx=33 --> x = pi/3 + kpix=π3+kπ
b. tan x = - sqrt3/3tanx=33 --> x = - pi/3 + kpx=π3+kp