How do you solve #6+h<1##?

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Answer 1 · 2017-04-26T17:18:39

See the solution process below:

Subtract #color(red)(6)# from each side of the inequality to solve for #h# while keeping the equation balanced:

#-color(red)(6) + 6 + h < -color(red)(6) + 1#

#0 + h < -5#

#h < -5#

Answer 2 · 2017-04-26T17:25:21

#h<-5#

#6+h<1#

#h < 1-6#

#h<-5#