How do you solve #(6/7)x - (2/3)=4 #?

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Answer 1 · 2018-04-17T06:26:32

#color(maroon)(x = 5 (4/9) " or " 5.44#

#(6/7)x - (2/3) = 4#

#L C M " "of " " 7, 3 = 21#

Taking 21 as L C M for L H S,

#((3* 6x) - (2 * 7) ) / 21 = 4#

#18x - 14 = 4 * 21 = 84, " cross multiplying"#

#18x = 84 + 14 = 98#

#x = 98 / 18 = (49 * cancel2 ) / (9 * cancel2) = 49 / 9#

#color(maroon)(x = 5 (4/9) " or " 5.44..#