How do you solve #5x+7=10# by clearing the fractions?

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Answer 1 · 2017-09-29T15:47:19

#x = 3/5#

#5x + 7 = 10#

Subtract both sides by #color(red)7#

#5x + 7 - color(red)7 = 10 - color(red)7#

#5x + 0 = 10 - 7#

#5x = 3#

Divide both sides by #color(red)5#

#(5x)/color(red)5 = 3/color(red)5#

#cancel((5) x)/cancel5 = 3/5#

#x = 3/5#