How do you solve $5x² - 6x – 3 = 0$ ?

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Answer 1 · 2016-07-10T14:34:58

$x_1=6/10+(4sqrt(6))/10=3/5+(2sqrt(6))/5$

$x_2=6/10-(4sqrt(6))/10=3/5-(2sqrt(6))/5$

We can use the quadratic formula to solve for the roots of

$5x^2-6x-3=0$

Solution:
$5x^2-6x-3=0$

We make use of the constants $a=5$ and $b=-6$ and $c=-3$

Now we make use of the Quadratic formula

$x=(-b+-sqrt(b^2-4ac))/(2a)$

$x=(-(-6)+-sqrt((-6)^2-4(5)(-3)))/(2(5))$

$x=(+6+-sqrt(36+60))/(10)$

$x=(+6+-sqrt(96))/(10)$

$x=(+6+-sqrt(16(6)))/(10)$

$x=(+6+-4sqrt(6))/(10)$

$x_1=6/10+(4sqrt(6))/10=3/5+(2sqrt(6))/5$

$x_2=6/10-(4sqrt(6))/10=3/5-(2sqrt(6))/5$

God bless....I hope the explanation is useful.

How do you solve 5x² - 6x – 3 = 05x² - 6x – 3 = 0?