How do you solve $-5x = -3x^2$ using the quadratic formula?

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Answer 1 · 2017-02-19T19:33:44

See the entire solution process below:

First, add $color(red)(3x^2)$ to each side of the equation:

$color(red)(3x^2) - 5x = color(red)(3x^2) - 3x^2$

$3x^2 - 5x = 0$

Now, factor an $x$ out of the expression on the left side of the equation:

$x(3x - 5) = 0$

Now, we can find the two solutions by equating each of the terms to $0$ and solving:

Solution 1)

$x = 0$

Solution 2)

$3x - 5 = 0$

$3x - 5 + color(red)(5) = 0 + color(red)(5)$

$3x - 0 = 5$

$3x = 5$

$(3x)/color(red)(3) = 5/color(red)(3)$

$(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 5/3$

$x = 5/3$

The solution is: $x = 0$ and $x = 5/3$

How do you solve -5x = -3x^2-5x = -3x^2 using the quadratic formula?