How do you solve $5x^2 + x = 3$ using the quadratic formula?

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Answer 1 · 2016-03-24T01:51:11

$x = (-1 +- sqrt61)/10$

Given

$ax^2 + bx + c = 0$

$=> x = (-b +- sqrt(b^2 - 4ac))/(2a)$

$5x^2 + x = 3 => 5x^2 + x - 3 = 0$

$=> a = 5$
$=> b = 1$
$=> c = -3$

$x = (-1 +- sqrt(1^2 - 4*5*-3))/(2*5)$

$x = (-1 +- sqrt(1 + 60))/(10)$

$x = (-1 +- sqrt61)/10$

How do you solve 5x^2 + x = 35x^2 + x = 3 using the quadratic formula?