How do you solve $5x^2 - 7x - 3 = 0$ using the quadratic formula?

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Answer 1 · 2018-03-31T17:35:59

$x=(7+sqrt109)/10$ or $(7-sqrt109)/10$

Quadratic formula gives the solution of $ax^2+bx+c=0$ as $x=(-b+-sqrt(b^2-4ac))/(2a)$

As in $5x^2-7x-3=0$ , $a=5$ , $b=-7$ and $c=-3$

$x=(-(-7)+-sqrt((-7)^2-4*5*(-3)))/(2*5)$

= $(7+-sqrt(49+60))/10$

i.e. $x=(7+sqrt109)/10$ or $(7-sqrt109)/10$

How do you solve 5x^2 - 7x - 3 = 05x^2 - 7x - 3 = 0 using the quadratic formula?