How do you solve #5x^2+5=0#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer sjc Nov 23, 2016 #x=+-i# Explanation: #5x^2+5=0# #5x^2=-5# #x^2=-5/5=-1# #x=sqrt(-1)# #x=+-i# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1334 views around the world You can reuse this answer Creative Commons License