How do you solve $5w^2 - 11w + 10 = 0$ using the quadratic formula?

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Answer 1 · 2015-10-20T17:37:05

The solutions are
$x=color(blue)((11+sqrt(-79))/10$

$x=color(blue)((11-sqrt(-79))/10$

$5w^2-11w+10=0$

The equation is of the form $color(blue)(aw^2+bw+c=0$ where:

$a=5, b=-11, c=10$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (-11)^2-(4*5*10)$

$= 121 - 200=-79$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-11)+-sqrt(-79))/(2*5) = (11+-sqrt(-79))/10$

The solutions are
$x=color(blue)((11+sqrt(-79))/10$

$x=color(blue)((11-sqrt(-79))/10$

How do you solve 5w^2 - 11w + 10 = 05w^2 - 11w + 10 = 0 using the quadratic formula?