How do you solve $5 n^{2} - 7 = 488$ $5n^2-7=488$ ?

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Answer 1 · 2018-06-20T08:17:45

$n = \pm 3 \sqrt{11}$ $color(brown)(n = +- 3 sqrt11$

$5 n^{2} - 7 = 488$ $5n^2 - 7 = 488$

$5 n^{2} = 495$ $5n^2 = 495$

$n^{2} = \frac{495}{5} = 99$ $n^2 = 495 / 5 = 99$

$n = \pm \sqrt{99} = \pm 3 \sqrt{11}$ $color(brown)(n = +- sqrt99 = +- 3 sqrt11$

How do you solve 5n^2-7=4885n2−7=4885n^2-7=488?