How do you solve $5/(y-2)=y+2$ ?

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Answer 1 · 2016-01-19T02:42:02

$y=+-3$

$5/(y-2)=y+2$

Multiply both sides times $(y-2)$ .

$5=(y+2)(y-2)$

Expand $(y+2)(y-2)$ .

$5=y^2-4$

Add $4$ to both sides.

$4+5=y^2$

Simplify.

$9=y^2$

Take the square root of both sides.

$+-sqrt 9=sqrt (y^2)$

Simplify.

$+-3=y$

Switch sides.

$y=+-3$

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