How do you solve #5/(y-2)=y+2#?

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Answer 1 · 2016-01-19T02:42:02

#y=+-3#

#5/(y-2)=y+2#

Multiply both sides times #(y-2)#.

#5=(y+2)(y-2)#

Expand #(y+2)(y-2)#.

#5=y^2-4#

Add #4# to both sides.

#4+5=y^2#

Simplify.

#9=y^2#

Take the square root of both sides.

#+-sqrt 9=sqrt (y^2)#

Simplify.

#+-3=y#

Switch sides.

#y=+-3#