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How do you solve #5^x=45#?

1 Answer

Oct 17, 2016

#x=2.365#

Explanation:

#5^x=45#

#log5^x=log45color(white)(aaa)#Take the log of both sides

#xlog5=log45color(white)(aaa)#Use the log rule #logx^a=alogx#

#(xlog5)/log5=log45/log5color(white)(aaa)#Divide both sides by log5

#x=2.365#

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