How do you solve $5^x=45$ ?

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Answer 1 · 2016-10-17T00:18:27

$x=2.365$

$5^x=45$

$log5^x=log45color(white)(aaa)$ Take the log of both sides

$xlog5=log45color(white)(aaa)$ Use the log rule $logx^a=alogx$

$(xlog5)/log5=log45/log5color(white)(aaa)$ Divide both sides by log5

$x=2.365$

How do you solve 5^x=455^x=45?