How do you solve 5(x+3)=7#?

1 Answer
Jim G.
Feb 21, 2017

#x=-8/5#

Explanation:

distribute the bracket on the left side of the equation.

#rArr5x+15=7#

Isolate 5x by subtracting 15 from both sides of the equation.

#5xcancel(+15)cancel(-15)=7-15#

#rArr5x=-8#

To solve for x, divide both sides by 5

#(cancel(5) x)/cancel(5)=(-8)/5#

#rArrx=-8/5#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#5(color(red)(-8/5)+3)=cancel(5)^1xx-8/cancel(5)^1+(5xx3)=-8+15=7#

#rArrx=-8/5" is the solution"#

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