How do you solve 5(x+3/4)^2-2=43?

1 Answer
Feb 7, 2017

x=-15/4" or "x=9/4

Explanation:

"Isolate " (x+3/4)^2 on the left side of the equation.

add 2 to both sides.

5(x+3/4)^2cancel(-2)cancel(+2)=43+2

rArr5(x+3/4)^2=45

divide both sides by 5

(cancel(5))/cancel(5)(x+3/4)^2=45/5

rArr(x+3/4)^2=9

Take the color(blue)"square root " of both sides.

sqrt((x+3/4)^2)=+-sqrt9

rArrx+3/4=+-3larrcolor(red)" 2 solutions"

color(blue)"Solution 1"

x=-3-3/4rArrx=-15/4

color(blue)"Solution 2"

x=+3-3/4=9/4