How do you solve $5=sqrt(r-3)$ ?

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Answer 1 · 2017-06-07T15:00:22

See a solution process below:

First, square both sides of the equation to eliminate the radical while keeping the equation balanced:

$5^2 = (sqrt(r - 3))^2$

$25 = r - 3$

Now, add $color(red)(3)$ to each side of the equation to solve for $r$ while keeping the equation balanced:

$25 + color(red)(3) = r - 3 + color(red)(3)$

$28 = r - 0$

$28 = r$

$r = 28$

How do you solve 5=sqrt(r-3)5=sqrt(r-3)?