How do you solve #5(3x + 12) = -15#?
1 Answer
Apr 28, 2018
Explanation:
#"divide both sides by "5#
#cancel(5)/cancel(5)(3x+12)=(-15)/5#
#rArr3x+12=-3#
#"subtract 12 from both sides"#
#3xcancel(+12)cancel(-12)=-3-12#
#rArr3x=-15#
#"divide both sides by 3"#
#(cancel(3) x)/cancel(3)=(-15)/3#
#rArrx=-5#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.
#5(-15+12)=5xx-3=-15=" right side"#
#rArrx=-5" is the solution"#
