How do you solve #5^(2x) = 8#?

1 Answer
Alan P.
May 13, 2016

#x=color(blue)((log_5 8)/2)~~color(blue)(0.646)#

Explanation:

If #5^(2x) = 8#
then
#color(white)("XXX")log_5 5^(2x)=log_5 8#

#color(white)("XXX")rarr 2x=log_5 8#

#color(white)("XXX")rarr x= (log_5 8)/2#

Use a calculator to obtain an approximate value for this expression.

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