How do you solve 4x+6y=12 for x?

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Answer 1 · 2017-02-09T13:56:12

See the entire solution process below:

First, subtract #color(red)(6y)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#4x + 6y - color(red)(6y) = 12 - color(red)(6y)#

#4x + 0 = 12 - 6y#

#4x = 12 - 6y#

Now, divide each side by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#(4x)/color(red)(4) = (12 - 6y)/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = (12 - 6y)/4#

#x = (12 - 6y)/4#

Or

#x = 12/4 - 6/4y#

#x = 3 - (2 xx 3)/(2 xx 2)y#

#x = 3 - (color(red)(cancel(color(black)(2))) xx 3)/(color(red)(cancel(color(black)(2))) xx 2)y#

#x = 3 - 3/2y#