How do you solve #4x-6=-2x-13#?
1 Answer
Apr 1, 2017
Explanation:
Collect terms in x on the left side of the equation and numeric values on the right side.
add 2x to both sides.
#4x+2x-6=cancel(-2x)cancel(+2x)-13#
#rArr6x-6=-13# add 6 to both sides.
#6xcancel(-6)cancel(+6)=-13+6#
#rArr6x=-7# divide both sides by 6
#(cancel(6) x)/cancel(6)=(-7)/6#
#rArrx=-7/6#
#color(blue)"As a check"# Substitute this value into the equation and if the left side equals the right side then it is the solution.
#"left side "=(4xx-7/6)-6=-14/3-18/3=-32/3#
#"right side "=(-2xx-7/6)-13=7/3-39/3=-32/3#
#rArrx=-7/6" is the solution"#
