How do you solve #4x^4 - 16x^2 + 15 = 0#?
1 Answer
May 3, 2018
Explanation:
for real coefficient equation
equation of n‐th degree exist n roots
so this equations exists 3 possible answers
1. two pairs of the complex conjugate of
2. a pair of the complex conjugate of
3. four real roots
first I guess I can use "Cross method" to factorizative this equation
it can be seen as below
so there are four real roots
