How do you solve $4x^2+7=23$ ?

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Answer 1 · 2018-04-25T19:08:44

see below...

First get the variable on one side and the constant on the other...
Subtract 7 from both sides.

$4x^2 = 16$

Now find $x^2$ so divide by 4 on both sides.

$x^2=4$

Now $sqrt$ both sides. Remember square rooting gives us a $+-$ answer.

$x = +-2$

How do you solve 4x^2+7=234x^2+7=23?