How do you solve $4x^2-6x-10=0$ using the quadratic formula?

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Answer 1 · 2015-08-10T07:11:55

The solutions for the equation are
$color(blue)(x=5/2, x=1$

$4x^2-6x-10 =0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=4, b=-6, c=-10$

The Discriminant is given by:
$Delta=b^2-4*a*c$

$= (-6)^2-(4*4*(-10))$

$=36+160$

$=196$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = (-(-6)+-sqrt(196))/(2*4) = (6+-14)/8$

$x=(6+14)/8 , x=(6-14)/8$

$color(blue)(x=20/8= 5/2$

$color(blue)(x=-8/8, x=-1$

How do you solve 4x^2-6x-10=04x^2-6x-10=0 using the quadratic formula?