How do you solve #4x^2-6x-10=0# using the quadratic formula?

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Answer 1 · 2015-08-10T07:11:55

The solutions for the equation are
#color(blue)(x=5/2, x=1#

#4x^2-6x-10 =0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=4, b=-6, c=-10#

The Discriminant is given by:
#Delta=b^2-4*a*c#

# = (-6)^2-(4*4*(-10))#

#=36+160#

#=196#

The solutions are found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

#x = (-(-6)+-sqrt(196))/(2*4) = (6+-14)/8#

#x=(6+14)/8 , x=(6-14)/8#

#color(blue)(x=20/8= 5/2#

#color(blue)(x=-8/8, x=-1#