How do you solve #4x^2 + 3x - 7 = 0#?

1 Answer
Aug 5, 2015

Solve: y = 4x^2 + 3x - 7 = 0.

Ans: 1 and #-7/4#

Explanation:

Since a + b + c = 0, use the shortcut --> 2 real roots: 1 and #(c/a = -7/4)#
Reminder of Shortcut .
When (a + b + c = 0) --> 2 real roots: 1 and c/a
When (a - b + c = 0) --> 2 real roots: - 1 and -c/a
Remember the Shortcut. It will save you a lot of time and effort.