How do you solve #4x^2 + 3x - 7 = 0#?

1 Answer
Nghi N.
Aug 5, 2015

Solve: y = 4x^2 + 3x - 7 = 0.

Ans: 1 and #-7/4#

Explanation:

Since a + b + c = 0, use the shortcut --> 2 real roots: 1 and #(c/a = -7/4)#
Reminder of Shortcut .
When (a + b + c = 0) --> 2 real roots: 1 and c/a
When (a - b + c = 0) --> 2 real roots: - 1 and -c/a
Remember the Shortcut. It will save you a lot of time and effort.

Related questions
See all questions in Comparing Methods for Solving Quadratics
Impact of this question
4649 views around the world
You can reuse this answer
Creative Commons License