How do you solve $4x^2 - 2x - 1 = 0$ ?

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Answer 1 · 2015-08-07T15:47:15

Solve $y = 4x^2 - 2x - 1 = 0$

Ans: $1/4 +- sqrt5/4$

Use the quadratic formula
$D = d^2 = b^2 - 4ac = 4 + 16 = 20 -> d = +- 2sqrt5$

$y = 2/8 +- (2sqrt5)/8 = 1/4 +- sqrt5/4$

How do you solve 4x^2 - 2x - 1 = 04x^2 - 2x - 1 = 0?