How do you solve $4 \sqrt{x + 3} = 18$ $4sqrt(x + 3) = 18$ ?

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Answer 1 · 2016-01-03T09:29:56

$x = \frac{69}{4}$ $x=69/4$

$4 \sqrt{x + 3} = 18$ $4sqrt(x+3)=18$

$\to {(4 \sqrt{x + 3})}^{2} = 18^{2}$ $rarr(4sqrt(x+3))^2=18^2$

$\to 16 (x + 3) = 324$ $rarr16(x+3)=324$

$\to 16 x + 48 = 324$ $rarr16x+48=324$

$\to 16 x = 324 - 48 = 276$ $rarr16x=324-48=276$

$\to x = \frac{276}{16} = \frac{69}{4}$ $rarrx=276/16=69/4$

How do you solve 4sqrt(x + 3) = 184√x+3=184sqrt(x + 3) = 18?