How do you solve $4sqrt(7 + 3z) = 2$ ?

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Answer 1 · 2015-08-19T12:47:00

$color(blue)(z=-9/4$

$4sqrt(7+3z)=2$

Squaring the L.H.S and R.H.S:

$(4sqrt(7+3z))^2=2^2$

$16(7+3z)=4$

$7+3z=4/16$

$7+3z=1/4$

$7*4+3z*4=1/4*4$

$28+12z=1$

$12z=1-28$

$z=-27/12$

$color(blue)(z=-9/4$

How do you solve 4sqrt(7 + 3z) = 24sqrt(7 + 3z) = 2?